4=(x^2-12x)/(x)

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Solution for 4=(x^2-12x)/(x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4 = (x^2-(12*x))/x // - (x^2-(12*x))/x

4-((x^2-(12*x))/x) = 0

4-((x^2-12*x)/x) = 0

(-1*(x^2-12*x))/x+4 = 0

(-1*(x^2-12*x))/x+(4*x)/x = 0

4*x-1*(x^2-12*x) = 0

16*x-x^2 = 0

16*x-x^2 = 0

x*(16-x) = 0

16-x = 0 // - 16

-x = -16 // * -1

x = 16

x*(x-16) = 0

(x*(x-16))/x = 0

(x*(x-16))/x = 0 // * x

x*(x-16) = 0

( x-16 )

x-16 = 0 // + 16

x = 16

( x )

x = 0

x in { 0} 

x = 16

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